Variables are not getting exported while running the script in cronjob

Shell Programming and Scripting
1

Hi All

Some how, variables are not getting exported while running the script in cronjob. Variable value is coming blank. But the variables are geting the value when the same script I am running manually. Any idea why?

When running the script in cron-job

user@server:~$ crontab -l
00 22 * * * $HOME/crt-offline-chkpnt.sh

When running the script manually

user@server:~$ ./crt-offline-chkpnt.sh

Thanks a lot to all in advance
C Saha

2

actually the file and the o/p is like this

$ cat crt-offline-chkpnt.sh

P4_COUNTER=`p4 -u cm -P cmpswd counters | grep journal | awk '{print $3}'`
echo "$P4_COUNTER" >aa.log

$ ./crt-offline-chkpnt.sh
$ cat aa.log
1157

No output when I have it in cronjob :frowning:

3

Hi,

have you checked the aa.log file, whats going in it
and post your cron entry as well

Gaurav

4

SORRY for the typo error in my previous post.

Yes I saw aa.log, its coming blank when its running by cronjob

This is cron settings

When running the script in cron-job

user@server:~$ crontab -l
00 22 * * * $HOME/crt-offline-chkpnt.sh

5

you may want to consider using explicit paths instead of paths with variables in them. quite honestly, i've never seen variables used in a cron table before.

if anything, you may want to check to see if:

  1. your script is running at all (check your local mailbox for cron errors(

and

  1. put in the full path to your 'p4' command.
6

Also try including your profile in the script your are calling via cron

7

Yes exactly. Both of your suggession worked. Its fine now.

8

I suggest that you change the default SHELL that CRON uses ( /bin/sh ?). I would change it to the default SHELL that your script is written in. You need to perform a man on cron to find it though. ' just a thought!

Good Luck!