Using printf in bash

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1 
printf "%5.5\n" "1234567890"

will print 12345 . How do I get it to print
67890
Essentially, I just want the last 5 characters rather than the first 5.

2 
num="1234567890"
printf "%d\n" ${num: -5}
3

This works for numbers. Use %s format specifier for characters:

$ var="ABCDEFGHIJK"
$ printf "%5s\n" ${var:5}
FGHIJK
or
$ printf "%5s\n" ${var: -3}
  IJK
4

Thanks!

5 
num="1234567890"
echo "${num#?????}"