unix

Shell Programming and Scripting
1

hi friends,

i have one problem in shell script.
i wrote for loop in sh.
i have one file called tmp in that list of lines are there like this.

suman
summeth
dfdfsdfa
dsfsdfsd

i am trying to read each line using for loop.

i want to read each line and write in to separate file.

my script is like this. but it is not working.
please help anyone.

for i in `cat $tmp`
do
echo $i
mv $i $var
csh script $i
done

2

Hope this is what you intended to do.

#! /bin/sh

for i in `cat $tmp`
do
     echo $i
     var=$i
     #mv $i $var
     csh script $i
done
3

thank u for your help.

but the script which u have given will only moves value to variable.

i.e in var.

but i want to write in a separate file.

regards
rajan

4 
var="$HOME/tmp_contents.txt"

echo $i >> $new_file
5

the above code is not working.

6

No it should have been like

#! /bin/sh
var="$HOME/tmp_contents.txt"
rm -f $var
for i in `cat $tmp`
do
     echo $i >> $var
     csh script $i
done
7 
while read line
do
echo $line
done < sourcefile > destfile
8

do you need each line read to go into a different new file - or are you just copying them all into the same new file?

9

Hi Rajan,

I need more clear on ur issue. The mv command accept two file names. Refer your code in the script.

mv $i $var

$i - has fetched from the text file. You mean, that is a existing file name? Or, the value need to be written in a separate file? If so, then what is the name for the new file? Either it is a single file or multiple files?

Please clear.

-Sethu.