Two arguments for optional switch

Shell Programming and Scripting
1

How to declare the two argument for optional switch ?

I have a script that search for a string in current or old zipped log file.
Im using a option something like this

${basename} [ -c <CRRNT_LOG_FILE> | -o <DATE:YYYY-MM-DD> <OLD_LOG_FILE> ]

Since $1 can have only one argument should be passed when user select swicth -c and -o need to have mandatory two arguments YYYY-mm-dd & OLD_FILE_NAME in case of -o switch.

Can we have this method ?? please suggest. Thanks in advance

2

Requirement not very clear. However, try googling on getopt.

regards,
Ahamed

3

Well, you could start with this, and modify accordingly:

#!/bin/ksh
badopt=0
current=
olddate=

while getopts c:o: opt
do
    case $opt in
        c)      current="$OPTARG";;
        o)      olddate="$OPTARG";;
        ?)      badopt=1;;
    esac
done
shift $((OPTIND - 1))

[ -z "$current" -a -z "$olddate" ] && badopt=1
[ -n "$olddate" -a $# -ne 1 ] && badopt=1

if [ $badopt -eq 1 ]; then
    echo "Syntax: $(basename $0) [ -c <CRRNT_LOG_FILE> | -o <DATE:YYYY-MM-DD> <OLD_LOG_FILE> ]" >&2
    exit 1
fi

if [ -n "$current" ]; then
    echo current log file: $current
elif [ -n "$olddate" ]; then
    old="$1"
    echo old log date: $olddate
    echo old log file: $old
fi

exit 0

Best regards,
Mark.

4

I have posted some wrong phrase in my previous post..

It should be something in this way .


${basename} [ -c <LOG_FILE> | -o <DATE:YYYY-MM-DD> <LOG_FILE> ]

The only difference between Current Log & Archive Log is that its suffix.

Current Log Format : LOG_FILE_Group1, LOG_FILE_Group2, LOG_FILE_Group3
Archive Log Format : LOG_FILE_Group[1-3]_2011-02-12.log.gz

If script running with option -o
Firstly It will check with DATE
Secondly It will Check with LOG_FILE

ls -ltr | grep -i 2011-02-12 | grep -i LOG_FILE_Group*

If $?=0

It does the gzgrep -i STRING LOG_FILE_Group* > OutputFile