To zip the files

Shell Programming and Scripting
1 
ls -c /dir1/dir2/test* | while read fileName
      do
               mv $fileName ${TargetDir}
               echo "Moving file: ${fileName} to ${TargetDir}" >> $LOGFILE
            done

In the above scenarion it will move all the files which is having pattern test* from the current directory to TargetDir directory.
What I need is after moving those files I want to zip all the files to one file

For example.I have files like below(the number of files can vary.It can be either 3 0r 10 etc)

test12
test23
test25

So it will move all the three files.Now I need a zip file like below.

test_Date.gz

, which will contains all the above three files.

2

If you want to zip multiple files to one file, you get one file after you unzip...
If you still want to do this,

gzip -c /dir1/dir2/test* > ${TargetDir}/test_Date.gz

---------- Post updated at 12:41 AM ---------- Previous update was at 12:37 AM ----------

or if you have zip

zip ${TargetDir}/test_Date.gz /dir1/dir2/test*

But the zip file holds the directory structure.
When you unzip in target dir, you see dir1/dir2 created in target

3

Thanks Srini..

When I do a gzip -c /dir1/dir2/test* > ${TargetDir}/test_Date.gz.All the files will be zipped into test_Date.gz file,But still all files will be there in that path itself.I dont want that files there in that path.I need to remove that file while I do zip

4

So, you remove it as soon as you finish gzip'ping.

rm /dir1/dir2/test*
5 
gzip -c /dir1/dir2/test* > ${TargetDir}/test_Date.gz

While I unizp the file

test_Date.gz

,its not giving me all the files.It is giving me only one file

6 
mv /dir1/dir2/test* ${TargetDir}/
cd ${TargetDir}
tar -cvzf test_Date.tar.gz ${TargetDir}/