Hiho,
I've got a variable $sth = `du -sh /home/$whoami`; where $whoami is actually logged user.
I want to have only the size of this directory eg. 2,7G.
I know its lame, but anyway.. how to do it?
What about
$sth = `du -sh /home/$whoami | cut -f1`;
since I think all you want is the first field.
Yeap, that's it!
Thanks a lot!