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UNIX for Beginners Q & A UNIX for Dummies Questions & Answers
1

hi ,

I have complete path
Sample:
/pkgs/Incoming/Completed/abc123_xyz.zip
/pkgs/Incoming/Completed/12_abcxyz.zip
/pkgs/Incoming/Completed/qwabcxyz.zip

i just need , so that i can copy these files to different directory,
abc123_xyz.zip
12_abcxyz.zip
qwabcxyz.zip

2

What's the question? :confused:

3 
$ cat sample
/pkgs/Incoming/Completed/abc123_xyz.zip
/pkgs/Incoming/Completed/12_abcxyz.zip
/pkgs/Incoming/Completed/qwabcxyz.zip
$ 
$ sed 's/.*\///' sample
abc123_xyz.zip
12_abcxyz.zip
qwabcxyz.zip
$

For copying try:

sed 's/.*\///' sample | while read line; do cp "$line" /different/directory; done

or

command that gives the complete path | sed 's/.*\///' | while read line; do cp "$line" /different/directory; done
4

i have command that gives the complete path , i need just the files names

5

I'm still not getting you fully, perhaps this?

find . -type f -exec basename {} \;

or this if you want to pass a file containing all the paths:

while read line; do basename $line; done < paths
6

Hope i make sense.

I use the below cmd to get the list of files that are modified than <temp> file in the <path> diretory

cmd:find <path> -name '*.zip' -type f -newer <temp> -print

i am getting all the list of files that are new or modified, with abs path, i want to copy all of these files to a different directory.