I have a file in which there are other file path and names
/home/data/abc.txt
/home/data/sdf.txt
/home/data/sdg.txt
how can I get the file names i.e. abc.txt sdf.txt sdg.txt
I searched the forum for sed command but it was confusing to me
Try:
perl -pe 's#.*/##' file
Also:
while read -r a; do basename "$a"; done <file
Or, if you like sed:
sed 's|.*/||' <file
--
Bye
while read line
do
file=`basename $line`
echo $file
done < yourfilename
assuming you need all file names irrespective of extension type.
You don't need backticks to do that 
OLDIFS="$IFS"
IFS="/"
while read LINE
do
set -- "$LINE"
shift $(( $#-1 ))
echo "Got $1"
done
IFS="$OLDIFS"
Shorter:
while read line
do
echo "Got ${line##*/}"
done < file
Here is one more way...probably quickest
awk -F"/" '{print $NF}' file.txt
We can't forget: egrep -o "[^/]+$" file
--
Bye
Try like...
awk -F'/' '{print $4}' test.txt
Hi Elixir/Bartus,
Can you please explain the use of HASH # here in code. How it works?
See the Advanced Bash Scripting Guide (String Operations). Most of those will work fine in BASH or KSH, and a few other shells as well.