String Array

UNIX for Beginners Q & A UNIX for Dummies Questions & Answers
1

I am having a string with the value:
str="name1, name2, name3, "

I want to traverse the list of elements. How do I loop them?

2

One way:

$ cat sloop
#! /usr/bin/ksh

str="name1, name2, name3, "

while [[ -n $str ]] ; do
        item=${str%%,*}
        str=${str#* }
        echo item = $item
done
exit 0
$ ./sloop
item = name1
item = name2
item = name3
3

Its easy to loop a string with spaces. So u can substitute the , with a space and then use that new string to loop using for....

str1="value1,value2,value3"
str2=`echo $str1 | tr "," " "`
#there is a space in between the second pair of quotes

for text in $str2
do
echo "$text"
done

4

Thanks Perderabo and Justsam.
Justsam logic seems to be bit easy.

Perderabo logic is not working if we have no space in str
str="name1,name2,name3, "

5

Here's my favorite way of doing this, similar to justsam but without piping $str through tr (UUOtr :smiley: )

str="name1, name2, name3, "

typeset IFS=' ,'
for i in $str
do
    echo $i$i                                                                                                                                                       
done
6

Yeah but your original post had ", " which is two characters and there is a superfluous separator ending the string. Sorry for believing what you wrote was accurately describing your problem. :stuck_out_tongue:

7 
str="name1,name2,name3, "

typeset IFS=' ,'
for i in $str
do
    echo $i
done

works with both ", " and ","