Storing Multiple Values in a Variable

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1

Hi,

My code is as below:

integer i=7
while ((i <= 5 ));
do
# test_out is a variable which contains data separated by "^".

a= `echo $test_out | cut -d"^" -f$i`

echo "$a"

(( i = i + 1));
done

From the above code, i kept $i after f so that i can capture all the data which is separated by "^". Here since "i" is incrementing 5 times, i want to store all the 5 values in variables such as a1,a2,a3,a4,a5 .

How can i do this. If i keep "i" after a it is not working. Ideally instead of keeping 5 commands for a, i want to do it in single shot by keeping ai. But it is not working.

If i do an echo "$ai", it must display all the 5 values since its looping 5 times.

Correct me if i mentioned some thing wrong. I am new to UNIX so it would be great if some body can help me out.

Thanks
Sandeep

2

Assuming you are using the Korn shell, the following example should show you how to do what you want

integer i=1

while ((i <= 5 ))
do
   eval 'a'$i'=$i'
   (( i++ ))
done

echo "$a1 $a2 $a3 $a4 $a5"