Splitting string with awk

Shell Programming and Scripting
1

Input:

Debris Linux is a minimalist, desktop-oriented distribution and live CD based on Ubuntu. 
It includes the GNOME desktop and a small set of popular desktop applications, such 
as GNOME Office, Firefox web browser, Pidgin instant messenger, and ufw firewall manager. 
Debris Linux ships with a custom kernel, a custom system installer called DebI, and
a script that makes it easy to save and restore any customisations made while in live mode.

How can i split this string with space(" ") and store words into array?

2 
awk '{for (i=1;i<=NF;i++) a[$i]++}END {for (i in a) print i,a}' input
3

How to do this using FS" " (field seperator)?

4

Your question doesn't make a whole lot of sense - if it did, you just answered it yourself.

You want to store this input in an array where? In AWK, or in the shell?

5

Definitely awk string.

6

There are punctuations in your string, so:

 awk -F"[ ,.]" '{for(i=1;i<=NF;++i) if($i!="")a[$i]} END {for(s in a) print s}' infile

If you insist on using FS, try this, it has the same output as the above code.

awk 'BEGIN {FS="[ ,.]"} {for(i=1;i<=NF;++i) if($i!="")a[$i]} END {for(s in a) print s}' infile