Split line before the pattern

Shell Programming and Scripting
1

Hi,

I am trying to use awk to split line before the pattern:

abcde 12345 67890 abcde 12345 67890 abcde 12345 67890 abcde 12345 67890 abcde 12345 67890 abcde 12345 67890 abcde 12345 67890

I need it to be like this:

abcde 12345 67890
abcde 12345 67890
abcde 12345 67890
abcde 12345 67890
abcde 12345 67890

What the easiest way to do it?

Thanks,
DJ

2 
sed 's/abcde/~abcde/g' < inputfilename | tr -s '~' '\n' > newfile

one way.

3

This is what I needed. Thanks!

4 
cat filename | tr 'abcde' '\nabcde'
5

tr is not replacing the string, the above command will change all the occurance of
'a' with '\n'
'b' with 'a'
'c' with 'd'
'e' with ''

6 
cat filename | tr 'abcde' '\nabcde'

the above code works fine here..

7

Or:
(use /usr/xpg4/bin/sed on Solaris)

sed 's/\([^ ]* \)\{3\}/&\         
/g' infile

If your sed implementation does not support re-interval:

sed 's/\([^ ]* [^ ]* [^ ]* \)/&\
/g' infile

or:

printf "%s %s %s\n" $(<infile)
8

Check you result characted 'e' will be missing. put some 'a' in your file and try that command.

$ cat filename
abcde 12345 67890 abcde 12345 67890 abcde 12345 67890 abcde 12345 67890 abcde 12
345 67890 abcde 12345 67890 abcde 12345 67890

l675389@ap1dev3 : $ cat filename | tr 'abcde' '\nabcde'

abcd 12345 67890
abcd 12345 67890
abcd 12345 67890
abcd 12345 67890
abcd 12345 67890
abcd 12345 67890
abcd 12345 67890

$ man tr

tr(1) tr(1)

NAME
tr - translate characters

SYNOPSIS
tr [-Acs] string1 string2

  tr -s [-Ac] string1

  tr -d [-Ac] string1

  tr -ds [-Ac] string1 string1

DESCRIPTION
tr copies the standard input to the standard output with substitution
or deletion of selected characters. Input characters from string1 are
replaced with the corresponding characters in string2. If necessary,
string1 and string2 can be quoted to avoid pattern matching by the
shell.