Sorting problem....

hey mate. ive got a sorting problem that i would like to share...

i made a script that sorts the bdf command and redirected the output to a file. the output of the file is:

691416 34% /
851552 7% /stand
7203048 31% /var
23637584 26% /var/adm/crash
2968864 37% /usr
1744096 16% /tmp
2381048 54% /opt
514848 51% /home
17% /home/com
986359 81% /home/appl
36% /backup_master
91% /backup
8227336 17% /home/com
2593361 36% /backup_master
5903593 91% /backup

please tell me how to sort out the file so that i can remove the ones in
bold (blue) because they are just copies of the file systems in bold (black).
please help me...

i don't think you really need to sort

cat file.txt  |sed -n '/[0-9]* [0-9]*%/p'

thanks mate. it works.... do you know how to further sort the output so that only the ones with 80% up are shown

$ cat file
691416 34% /
851552 7% /stand
7203048 31% /var
23637584 26% /var/adm/crash
2968864 37% /usr
1744096 16% /tmp
2381048 54% /opt
514848 51% /home
17% /home/com
986359 81% /home/appl
36% /backup_master
91% /backup
8227336 17% /home/com
2593361 36% /backup_master
5903593 91% /backup
$ awk -F"[ %]" ' $2 > 80 ' file
986359 81% /home/appl
5903593 91% /backup

thanks mate. i also found a nifty syntax that does the same... still, thanks...

cat file|grep [8-9][0-9]%