Simple bash script menu

Dear Sir,

May I know how do I go about adding the following feature into the script below:

When user enter values other than 1,2,3,4,

a) Message �Wrong entry !!! Pls select 1,2,3 or 4� is displayed
b) The screen is cleared again and the menu is displayed.

#!/bin/bash
clear
var=1
until [ $var -eq 4 ] 
do
echo "Menu"
echo "(1) Item 1"
echo "(2) Item 2"
echo "(3) Item 3"
echo "(4) Exit"
read -p "Enter your choice " var
clear
echo "Your choice is $var"
done

I've tried adding * but it returns an syntax error.

Thank you.

Hi Fusetrips,
Try using the below its off one of the scripts I already have built.

*) echo "Please select a valid choice ";
echo "Press a key to return to the menu. . ." ; read ;;
esac
:
done

to the user running the script it looks like the below

Enter your menu choice:
30
Please select a valid choice
Press a key to return to the menu. . .

once a key has been pressed it returns to the menu

Try using a case statement or an if statement.