scripting

Shell Programming and Scripting
1

i want to send a file that I have saved using a vi editor to another shell script. I also want that script (2nd one) to display the contend of the file.

Please help me by giving the code.

2

send that file as an argument to second script
and if you want to display only the content you can use cat command in that second script
secscript filename
cat $1--->this is what you have to write in secscript

3

could you please clarify with a code . I am just learning scripting by experimenting . pl

4

$ cat shell1.ksh
sh shell2.ksh /unix/passme.txt

$cat shell2.ksh
echo $1
cat $1

Hi,
you can pass the filename with path to the second shell as a Parameter.
in the second you will get that as $1 and you can use that.

in the above example "/unix/passme.txt" is the filename which i passing to shell2.ksh from shell1.ksh. shell2.ksh will get that as $1 and use it.

5

let file1 be your filename what you saved in vi editor
open a new file namely file2.sh
in that just write
cat $1

then run that as
file2.sh file1

then it will display the content of file1

6

but my problem is that the name of the file will be dynamic. i have a shell script (1st) that displays a splash screen , then the user can chose a vi editor and save the file and quits the editor. At that time I want the contend of the file to be send to the next shell script .

pl help

7

can you post your first script..

8

it just displays a splash screen using the dialog utility. I don't how to do the remaining. pl help