Script to run on 2 4 and 7 day of the month

Shell Programming and Scripting
1

I am looking for a unix script which could run a job on 2, 4 and 7 working day of the month.

if the days are falling on the saturday/sunday. it should run on the next day.

Thank you..

2

Please give way more detail. How can the 2./4./7. WORKING day fall on a Sunday?

cron will schedule jobs according to a time pattern up to you. If that is not doable/sufficient, you'll need to add time control logics to you script.

3

our requirement is that we need to create a touch file on 2 4 and 7 th working day of the each month ...

If the days falls on saturday/sunday, the touch file should be created on next working day.

4

Hi.

It seems that we need to create a list of the working days in a month, then select days 2,4,7 from that list and check if today is in that list. Here is a demonstration of those steps, using utilities that are found in GNU/Debian as noted:

#!/usr/bin/env bash

# @(#) s3       Demonstrate display of days in month: "working", not weekend.

D=dateutils.dseq
# Utility functions: print-as-echo, print-line-with-visual-space, debug.
# export PATH="/usr/local/bin:/usr/bin:/bin"
LC_ALL=C ; LANG=C ; export LC_ALL LANG
pe() { for _i;do printf "%s" "$_i";done; printf "\n"; }
pl() { pe;pe "-----" ;pe "$*"; }
db() { ( printf " db, ";for _i;do printf "%s" "$_i";done;printf "\n" ) >&2 ; }
db() { : ; }
C=$HOME/bin/context && [ -f $C ] && $C $D date grep

pl " First day of current month:"
date --date=today +%Y-%m-01

pl " Day 30 days in the future:"
date --date="now + 30 days" +%F

# Get list of working days from first of month.
$D -s "ss" $( date --date=today +%Y-%m-01 ) "$( date --date="now + 30 days" +%F )" -f "%F %a" > f1

pl " Sample of output:"
head -8 f1

pl " Select days 2,4,7:"
sed -n -e '2p' -e '4p' -e '7p' f1 |
tee f2

pl " Test if today is in the 3-day list:"
today=$( date +%F )
pe " today is $today"

if grep "$today" f2 >/dev/null
then
  pe " YES, touch the file now."
else
  pe " Today is NOT day 2,4,7, skipping touch."
fi

exit 0

producing (luckily today seems like the 7th working day):

$ ./s3

Environment: LC_ALL = C, LANG = C
(Versions displayed with local utility "version")
OS, ker|rel, machine: Linux, 3.16.0-4-amd64, x86_64
Distribution        : Debian 8.4 (jessie) 
bash GNU bash 4.3.30
dateutils.dseq dseq 0.3.1
date (GNU coreutils) 8.23
grep (GNU grep) 2.20

-----
 First day of current month:
2016-06-01

-----
 Day 30 days in the future:
2016-07-09

-----
 Sample of output:
2016-06-01 Wed
2016-06-02 Thu
2016-06-03 Fri
2016-06-06 Mon
2016-06-07 Tue
2016-06-08 Wed
2016-06-09 Thu
2016-06-10 Fri

-----
 Select days 2,4,7:
2016-06-02 Thu
2016-06-06 Mon
2016-06-09 Thu

-----
 Test if today is in the 3-day list:
 today is 2016-06-09
 YES, touch the file now.

Not trivial, but an interesting problem, however, end cases are not tested, so some work may be needed to turn these ideas into a production script.

See man pages for details.

Best wishes ... cheers, drl

5

Great work ... Thank you mate,

getting this error

+ date '--date=now + 30 days' +%F
2016-07-09
++ date --date=today +%Y-%m-01
++ date '--date=now + 30 days' +%F
+ dateutils.dseq -s ss 2016-06-01 2016-07-09 -f '%F %a'
./ra_test.sh: line 27: dateutils.dseq: command not found
+ pl ' Sample of output:'
+ pe
+ printf '\n'
6

Install date-utils?

apt-get install date-utils
7

is there any other way to over come it without installing the data utility ..

8

Hi.

First of 17 million hits from Google search for linux sequence of dates display OR compute: unix - How to generate a sequence of dates given starting and ending dates using AWK of BASH scripts? - Stack Overflow

You'll need to do work on those selections to create a list similar to that from dateutils.dseq .

Best wishes ... cheers, drl

9

we are currently on Redhat linux 6.5..The command apt-get install date-utils asked for execution is for Ubuntu Linux.

10

Hello tradingspecial,

Could you please check following script and let me know if this helps you.

cat script.ksh
PWD=`pwd`
OUT_FILE=$PWD"/output_file"
ZERO=0
if [[ -f $OUT_FILE ]]
then
        echo "Run script here."    ####You could call you script/command here.
        rm $OUT_FILE
        exit;
fi
VAL=`cal 12 2016 | awk -vout_file="$OUT_FILE" 'NR>2{for(i=1;i<=NF;i++){if(($i==2 || $i==4 || $i==7) && (i==7 || i==1)){print $i " of this month is falling on a working day." > out_file;print 1} else {print 0}}}'`
 
if [[ $VAL == $ZERO ]]
then
        echo "Run script here."   ####You could call you script/command here.
fi

So following things also should be done by you apart from above code.
i- Create a script(as above shown) with proper permissions.
ii- Schedule an entry in cron by doing crontab -e .
iii- Entry should be like that so it should run that script for each month from dates 1 to 8.
It could be like as follows, where I am running script from each month's 1st to 8th date on 1 AM of your box timing.

0 1 1-8 * * /path/to/exact/script.ksh

iv- Also in above code I have tested it with command cal 12 2016 because it has 2nd of October falling on Sunday, you could change it to cal in above code.
A big disclaimer here, I haven't tested it at all, this goes to your plate, please do proper testing and get back to us then.

Thanks,
R. Singh