Replace second to last but one consecutive occurence

Shell Programming and Scripting
1

Hi Unix Mates,

I have requirement where in which I have to replace second to last -1 occurence of space with a word and last occurence of a space with a word and a space,input would be a file.

Desired result:
Second consecutive to last-1 occurence of space replace with: HRU
LAST consecutive occurence : WRU[SPACE]

input

cat myfile
Wow what a[8spaces]wonderful feeling to be alive 

<Code>
Wow what a HRUHRUHRUHRUHRUHRUHRUWRU wonderful WRU feeling to be alive

Thanks iN ADVANCE!!!

2

Hello Kingcobra,

Following may help you in same.

echo "Wow what a wonderful feeling to be alive" | awk '{for(i=1;i<=NF;i++){if(i==4){print "HRUHRUHRUHRUHRUHRUHRUWRU"} {if(i==5){print "WRU"}} {if(i!=4 || i!=5){print $i}}}}' ORS=" "

Output will be as follows.

Wow what a HRUHRUHRUHRUHRUHRUHRUWRU wonderful WRU feeling to be alive

Thanks,
R. Singh

3

@Kingcobra: could you elaborate what a consecutive space means to you. Is your input file is incorrect? What have you tried?

--
@Ravindersingh that is not a solution...

4

Thanks mates.

Actaullt my spaces got supressed when I have put it inside code tag
Help required is
First space --->Do nothing
Second consecutive space--->REPLACE WITH HBU
third space --->REPLACE WITH HBU

n-1th consecutive space ----> REPLACE WITH HBU
Last space in consecutive sequence--->REPLACE WITH WBU[space]

Thanks Scrutinizer,Singh for your help:b:

5

Try:

sed -e 's/\(  *\) /\1WRU /g' -e :a -e 's/  \([HW]RU\)/ HRU\1/;ta' file

I believe there should be six HRU's (2nd until last -1) not 7, correct?

6

Bulls eye!!! Scrutinizer you are an amazing guy.Proud to be in this forum