Python: Comparison is not working for me

Shell Programming and Scripting
1

Guys it is very simple script , but for some reason my IF condition is not matching.

from sys import argv
import os
filename='testdata.txt'

txt=open(filename)
while 1:
 
 line= txt.readline()
 if not line:
	break
 line=line.strip('\n')
 sp=line.split(" ")
 command =sp[2]+ " " +sp[3]+ " " +sp[4]
 print command
 re=os.system(command)
 print "output:",re
 print "expected:",sp[0]
 if re == exp:
  print "Testcase Passed", sp[1]
 else:
  print "Testcase Failed", sp[1]

the if condition is always failing for me....

2

Where do you set exp ? ...

3

opps my mistake the code is actually

from sys import argv
import os
filename='testdata.txt'

txt=open(filename)
while 1:
 
 line= txt.readline()
 if not line:
	break
 line=line.strip('\n')
 sp=line.split(" ")
 command =sp[2]+ " " +sp[3]+ " " +sp[4]
 print command
 re=os.system(command)
 print "output:",re
 print "expected:",sp[0]
 if sp[0] == re:
  print "Testcase Passed", sp[1]
 else:
  print "Testcase Failed", sp[1]

i got the indication of failure , the out put of os.system is 1 and sp[0] is '1'.
how i can handle such conditions..?

4

probably because of the data types. try converting sp[0] to an integer as well:

 if int(sp[0]) == re:
5

that worked , thanks :slight_smile: