Printing the lines using search patterns

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1

Hi all ,

i need an help here.!!!! i have a file that contains /etc/passwd files from some servers.

i need a script which search for presence of a user in the servers.
like if i give 51144 to the script. the should be o/p

Please help on this.....

2 
awk -v FS=":" -v USER="51144" '
BEGIN { print "user:" USER; }
{
        if(NF < 2)              TITLE=$1
        else if($1 == USER)     print TITLE;
}' < data
3

Or try..

awk '/51144/{print $1}' RS= inputfile
4

thanks for ur reply Corona688 and michaelrozar17, but i really didnt get what i expected .
ok may be, i will explain little further . i have file thats look like below

like that there are nearly 100 servers , i just want to print the user and the servers where account exists.

5

Something like this..?

 awk -v usr="root" 'BEGIN{print "User:" usr} $0 ~ usr {print $1}' RS= inputfile