Printing another column using awk and input data

Shell Programming and Scripting
1

Hi, I have data of the following type,

chr1 234 678 39 852 638 abcd 7895
chr1 526 326 33 887 965 kilj 5849

Now, I would like to have something like this

chr1 234 678 39 852 638 abcd 7895 <a href="http://unix.com/thread=chr1:234-678">Link</a>
chr1 526 326 33 887 965 kilj 5849 <a href="http://unix.com/thread=chr1:526-326">Link</a>

basically, this is nothing but first column separated by a colon ":" and the second and third columns with a hyphen "-".

My files has around 20000 records.

All helps appreciated. Thanks

2 
awk '{$0=$0" <a href=\"http://unix.com/thread="$1":"$2"-"$3"\">Link</a>"}1' infile > outfile
3 
awk '{printf "%s <a href=\"http://unix.com/thread=%s:%s-%s\">Link</a>\n",$0,$1,$2,$3}' infile
4

Thanks scrutinizer and bartus.

But, the last column is being printed without a tab in between.

How do I add a tab between the last and pre-last column?

Thanks

5

Here?

awk '{$0=$0"\t<a href=\"http://unix.com/thread="$1":"$2"-"$3"\">Link</a>"}1' infile > outfile
6

Not sure what you means with the last column. Do you mean this?

awk '{printf "%s\t<a href=\"http://unix.com/thread=%s:%s-%s\">Link</a>\n",$0,$1,$2,$3}' infile