print in incremental order a sentence

Shell Programming and Scripting
1

Dear help!

I want to print

The number i is number i

let i=1 to 5

output
should be like

The number 1 is number 1
The number 2 is number 2
The number 3 is number 3
The number 4 is number 4
The number 5 is number 5

Would be gr8 if you mke this with awk
Thanks

2 
$ echo "10" | nawk '{for(i=1;i<=$0;i++)print "The Number is " i " is Number " i}'  
The Number is 1 is Number 1
The Number is 2 is Number 2
The Number is 3 is Number 3
The Number is 4 is Number 4
The Number is 5 is Number 5
The Number is 6 is Number 6
The Number is 7 is Number 7
The Number is 8 is Number 8
The Number is 9 is Number 9
The Number is 10 is Number 10
3

this can be done with for loop ...

 
$ for i in 1 2 3 4 5
> do
> echo "the number $i is number $i"
> done
the number 1 is number 1
the number 2 is number 2
the number 3 is number 3
the number 4 is number 4
the number 5 is number 5
4

In the for loop, you do something like this also.

 
for i in $(seq 10) # if you have seq command in your system
5

Thanks,
now suppose i want

for i=1 to 8 and j = 1 to 10

discoi in diskj

ouput should look like

disco1 in disk1
disco1 in disk2
......
...
disco1 in disk8

disco2 in disk1
disco2 in disk2
....
...
disco2 in disk8

etc etc

awk is preferred,thanks in advance
thanks

6 
$ echo "3 4" | nawk '{for(i=1;i<=$1;i++){for(j=1;j<=$2;j++)print "disco"i" in disk"j}}'                                                           
disco1 in disk1
disco1 in disk2
disco1 in disk3
disco1 in disk4
disco2 in disk1
disco2 in disk2
disco2 in disk3
disco2 in disk4
disco3 in disk1
disco3 in disk2
disco3 in disk3
disco3 in disk4
7 
$ echo "8" | nawk -v j_val=10 '{for(i=1;i<=$0;i++) for(j=1;j<=j_val;j++) print "Disco " i " in Disk " j}'
8

thanks a lot