pattern matching

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1

Hello all,

I'm having a problem and would like to know if anyone has a solution. I would like to search my /etc/hosts file for and ip address say 10.1.1.1. I'm currently have this IP address as a variable, but I only what it to match it.

I have grep $IP /etc/hosts.
grep `\< $IP>\` /etc/hosts
grep "IP" /etc/hosts
sed 's/\^$IP\$/p' /etc/hosts

This would give my everything like 10.1.1.1*, but I only want 10.1.1.1.
I have problem with passing a vaiable to the sed command when I want to use reg expression. I

2

Try
grep "\<$IP\>" /etc/hosts
awk -vip="$IP" '{ if ( $1 == ip ) { print } }' /etc/hosts

Cheers
ZB

3

use

grep -w "$IP" /etc/hosts

4

Thanks bhargav,

I knew it was something easy.