Pattern manipulation in korn shell script using sed.

Shell Programming and Scripting
1

Hi,

Could any one let me know, how can I cut the last field in below mentioned line.

net,-hopcount,0,-netmask,255.255.255.0,,,,,192.168.37.0,10.253.0.1
net,-hopcount,0,-netmask,255.255.255.0,,,,,192.168.1.0,10.253.0.1 net,-hopcount,0,-netmask,255.255.255.0,,,,,192.168.38.0,10.253.0.1
net,-hopcount,0,-netmask,255.255.255.0,,,,,192.168.2.0,10.253.0.1
net,-hopcount,0,-netmask,255.255.255.0,,,,,192.168.39.0,10.253.0.1
net,-hopcount,0,,0,10.14.185.1
net,-hopcount,0,-netmask,255.255.255.0,,,,,0,10.14.185.1
net,-hopcount,0,-netmask,255.255.0.0,,,,,10.253.0.0,10.253.0.1
net,-hopcount,0,-netmask,255.255.255.0,,,,,192.168.9.0,10.253.0.1
net,-hopcount,0,-netmask,255.255.255.0,,,,,192.168.36.0,10.253.0.1

I want to get all the gate way mentioned in bold above., ie last 10.253.0.1. we can't use the filed separator as " , " while using awk as the number of parameter varies. Tried all awk but hope can do it using sed. would like to know the format.

Thanks,
Ajilesh

2

With awk you can get the last field with $NF:

awk -F, '{print $NF}' file

Regards

3

Try this..

$ awk -F"," '{ print $NF }' <<File name >>

4

It works...!! Great..!!