Pass variable to php from html form

Shell Programming and Scripting
1

I am sure this is easy but I can't figure it out...

Here is the form.

<?php
$searchString = $_POST["search"];
if (!isset($_POST['submit']))
?>
<html>
<head>
<title>Personal INFO</title>
</head>
<body>
<form method="post" action="search.php">
<input type="text" size="20" maxlength="20" name="search">
<br />
<input type="submit" value="submit" name="submit">
</form>
</body>
</html>

Here is the script I am trying make work.

$searcher = new
FileSystemStringSearch('/logs/','$searchString');
$searcher->run();
         
if($searcher->getResultCount() > 0) {
    echo('<p>Searched "'.$searcher->getSearchPath().'" for string
<strong>"'.$searcher->getSearchString().'":</strong></p>');
    echo('<p>Search term found <strong>'.$searcher->getResultCount().'
times.</strong></p>');
    echo('<ul>');
        foreach($searcher->getResults() as $result) {
            echo('<li><em>'.$result['filePath'].', line
'.$result['lineNumber'].'</em>:<br />
     
'.$searcher->highlightSearchTerm($result['lineContents']).'</li>');
        }
    echo('</ul>');
} else {
    echo('<p>Searched "'.$searcher->getSearchPath().'" for string
<strong>"'.$searcher->getSearchString().'":</strong></p>');
    echo('<p>No results returned</p>');
}
?>

This is the result...
Searched "/logs/" for string "$searchString":
No results returned

Thanks in advance for the help.

2

Things in single quotes are interpreted as literal strings, so you're literally hunting for '$searchString' instead of the value you wanted. You don't need to quote a single variable parameter for anything anyway. Try just $searchString instead of '$searchString'