Pass string from shell script to java

Shell Programming and Scripting
1

Hi,

I,m writing a program in shell script and currently this script is calling a java program.

I have a problem to pass string variable from my shell script to the java program. I don't know on how to pass it and how the java program can call what I have pass from the shell script.

This is my shell script :

for file in $list_file; do

mv $INPUT_PATH/$file $INPUT_PATH/CIM301${day}_${count}.txt
count=`echo $count + 1 | bc`

done

I want to pass the variable $list_file to my java program..

Anybody can help??

Thanks in advance.

2

Well, it's as simple as putting the value of your shell variable in the call to the java program. The java program doesn't really *call* the argument(s); it accesses and maybe processes them.

Here's a plain-vanilla java program that displays the input parameters:

$ 
$ cat testArg.java
class testArg {   
  public static void main (String args[]) {
    System.out.println("\nInside the java program.");
    System.out.println("You passed : " + args.length + " parameters.");
    for (int i=0; i<=args.length-1; i++) {                             
      System.out.println("Parameter # " + (i+1) + "\tValue = " + args);
    }
  }
}

$
$ java testArg ant bat cat dog eel

Inside the java program.
You passed : 5 parameters.
Parameter # 1   Value = ant
Parameter # 2   Value = bat
Parameter # 3   Value = cat
Parameter # 4   Value = dog
Parameter # 5   Value = eel
$
$

I believe "list_file" contains a list of files separated by whitespace.
Here's how you can pass it to the java program shown above:

$
$ cat test_scr.sh
file_list="file1 file2 file3 file4"
echo "In the shell script."
echo "Value of file_list = $file_list"
echo "Now passing file_list to the java program..."
java testArg $file_list

$
$ . test_scr.sh
In the shell script.
Value of file_list = file1 file2 file3 file4
Now passing file_list to the java program...

Inside the java program.
You passed : 4 parameters.
Parameter # 1   Value = file1
Parameter # 2   Value = file2
Parameter # 3   Value = file3
Parameter # 4   Value = file4
$
$

tyler_durden

____________________________________
"The things you own end up owning you."

3

Hi durden_tyler,

Thanks for your code. I have try it but I encounter some error. For your info my java code and shell script is at different location.So, I try to specify the java code location into your shell script :

java .portal.DEV.PDEVFN12.Batch.common.Java.src.com.p1.bccs.batch.common.fileloader.testArg $file_list

I got this error when I run your script :

test_scr.ksh[2]: ^M: not found.
test_scr.ksh[5]: ^M: not found.
test_scr.ksh[6]: ^M: not found.
In the shell script.
Value of file_list = file1 file2 file3 file4
Now passing file_list to the java program...
Exception in thread "main" java.lang.NoClassDefFoundError: /portal/DEV/PDEVFN12/Batch/common/Java/src/com/p1/bccs/batch/common/fileloader/testArg

Thanks for your help:b:

4

The "^M" error is thrown due to differences in end-of-line characters across OSes. It might've been introduced when you ftp'ed your file with incorrect format from one OS to another, or when you copied/pasted the code to a text editor that does not "recognize/set" the end-of-line character of the underlying OS.
The NoClassDefFoundError is pretty self-explanatory - the class was not found by your JVM. Reset your classpath accordingly.

tyler_durden