number of words in delimited string

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1

Hi,

I'm looking for one liner code for counting number of words in a delimited string..

I know about wc -w ..but if i give wc -w a.txt,b.txt it won't work with delimited sting as it was looking for files with a.txt and b.txt

I know there will be a simple solution..i couldn't resolve..myself

Ex:In a string a.txt,b.txt,abacd i need the output as 3..

Please help!

2

On (of many) ways: Change the delimiter to a newline

echo "a.txt,b.txt,abacd"|tr ',' '\n'|wc -l
3
3 
$
$
$ echo "a.txt,b.txt,abacd" | perl -lne 's/[^,]//g && print length($_)+1'
3
$
$ echo "a.txt,b.txt,abacd" | perl -lne '$_.=","; print s/,//g'
3
$
$ echo "a.txt,b.txt,abacd" | awk '{$0=$0","; print gsub(",",x)}'
3
$
$ # and Perl equivalent of Franklin52's awk script ;)
$ echo "a.txt,b.txt,abacd" | perl -F, -plane '$_=$#F+1'
3
$
$

tyler_durden

4

Or:

awk -F, '{print NF}' file
5

Thank You Guys! It works like a charm!

6

To get the count of the no of occurrences of the given delimiter (i.e) comma ',' here

awk -F, '{print NF-1}' file