need to retrieve values of parameter

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1

Hi,

I am just new to this shell scripting wizard..i have a text file which contains content as below:

Parameter=10;

What should be the script which only fetches the value 10 not the Parameter.
The idea is to get the logic behind getting the value alone not its parameter,....

2

Use awk
Following will print value on screen:

awk -F'(=|;)' '{print $2}' inputFile

TO store in some variable:

val=$(awk -F'(=|;)' '{print $2}' inputFile)
echo $val
3

thanks anurag..!! it works..

---------- Post updated at 04:08 PM ---------- Previous update was at 03:21 PM ----------

It will be great if you help us in below :
We have a file with below contents
build number=1
Release number=23

& if we use the above mentioned command :
then..
it will gv both 1 & 23 as results.

What should be the way to get only 1 or only 23...?

4 
while read line
do
    val=$(echo $line | awk -F'(=|;)' '{print $2}')
    echo $val
    <Your other script lines processing val>
    <Your other script lines processing val>
    .........................
done < inputFile

If lines in inputFile don't have semicolon at the end, then awk command may be written as: (Above also will work though)

awk -F= '{print $2}'
5

Hi Anurag,

I tried with this script but its still giving all the values at a go.
Please find the attachment comprising of the script,text file & result..
Let me know where i am wrong..!!!
Thx a lot for ur help...

6

What input to the script (if any)?
What processing in the script?
What expected output from the script?

7

your script will be:

param=$1
val=$(awk -F= -v param=$param '$0 ~ param{print $2}' inputFile)
echo $val

Now while running the script, you need to pass paramtername that you want to see, i.e.

script.ksh parameter1

OR

script.ksh parameter2