Hi folks,
I would like to get familiar with shell script programing.
The first task is:
write a shell script that:
scans your home-folder + sub-directory for all txt-files that all users of your group are allowed to read and write
then output these files sorted by date of last modification
the full path and the file's rights of each file shall also be shown!
so when I execute the script it shall give me an output like this:
"filename", "date of last modification", "rights of file", "full path"
I already tried something with "AWK" and several pipes between awk and the regular shell but I got a little bit mixed up so
I would be very pleased for any kind of help!
please post your awk solution. It looks like a home work 
that's how it looks like "now":
I made a lot of changes and so there's now a syntax error ,too.
after this awk I tried to get a list of directories to a file (temporary.any)
afterwards I wanted to read this file to do a cd "current directory from list" and an ls -l
to get it filter
but now I am lost ...
there must be a more simple way to solve it?
#! /bin/bash
find ~/ -type f -name "*.txt" -perm -'u=,g=rw,o=' -ls |
awk '/{
n = split ($11, dateinamen,"/");
dateiname = dateinamen[n];
print "FILENAME :"dateiname,"PATH :"$11,"FILERIGHTS :"$3,
"LAST CHANGE :", $9, $8 \}' >> temporary.any
---------- Post updated 04-10-11 at 08:50 AM ---------- Previous update was 04-09-11 at 12:55 PM ----------
So I found a solution:
#! /bin/bash
find ~ -name "*.txt" -printf "%M %f %TY%Tm%Td%TH%TM%TS %TY %Tm %Td %TH %TM %p\n" | sort -nk3 |
awk '/^....rw/{
filecnt = filecnt + 1
printf ("No. %s", filecnt);
printf (" *** filename: %s", $2 )
printf (" *** filerights: %s", $1);
printf (" *** last change on: %s.%s.%s um %s:%s h\n",$6, $5, $4, $7, $8)
printf (" *** file path: %s\n", $9);
printf ("\n");
}'
So I found a solution:
#! /bin/bash
find ~ -name "*.txt" -printf "%M %f %TY%Tm%Td%TH%TM%TS %TY %Tm %Td %TH %TM %p\n" | sort -nk3 |
awk '/^....rw/{
filecnt = filecnt + 1
printf ("No. %s", filecnt);
printf (" *** filename: %s", $2 )
printf (" *** filerights: %s", $1);
printf (" *** last change on: %s.%s.%s um %s:%s h\n",$6, $5, $4, $7, $8)
printf (" *** file path: %s\n", $9);
printf ("\n");
}'
[/quote]
I just wondered how to change this not looking for file endings!
in Linux files aren't identified by file extension so now want to check the files mimetype using the "file" command
but I cant find a solution that can be adopted to my first solutin where I was looking for the file extension? any ideas?
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