Need Help on For Loop

Shell Programming and Scripting
1

Hi

I need help i Loop format

If i use the Following syntax

$ for i in `echo "Hello world"`
do
echo $i
done

Output is:
Hello
world

But i need Output in One line "Hello world"

Can any one help?

If i use while loop it works?
I want to use for loop only.

Thanks in advance

2

Here is what you want, but why do an echo of that? AN echo "hello world" would give you what you request

for i in "echo hello world"
do
echo $i
done

3

Hi
Thanks for your prompt response.

Here is my question:

In My script at some place I'm reading one file in for loop:

cat file_name
abc|xyz|Hello World|

for i in `cat file_name`
do
x=echo $i|cut -f1 d'|'
y=echo $i|cut -f2 d'|'
z=echo $i|cut -f3 d'|'

command1
perform action

command2
perform action

done

The above for loop result is splitting into 2

abc|xyz|Hello
World

I want to read "Hello World" as one argument

please help

Thanks

4

have a try with awk instead of cut, it should be ok after.
This sounds like school work, be aware that it's not excepted here..

Cheers

Jason

5

for i in `echo "Hello world"`
do
echo "$i \c"
done

6 
#!/bin/ksh

while IFS='|' read command1 command2 command3 junk
do
   echo "[$command1]"
   echo "[$command2]"
   echo "[$command3]"
done < file_name
7

Thanks for your response and support.
I managed to solve the problem.

Converting spaces into strings and putting it back. coz "for loop" can't read as continuous line if there is space in between (as i know)

cat file_name
abc|xyz|Hello World|
xas|ewe| Simple QA|
(Here i know space is only for 3rd argument)

for i in ``awk '{gsub(" ",",");print}' file_name`
do
x=echo $i|cut -f1 d'|'
y=echo $i|cut -f2 d'|'
z=echo $i|cut -f3 d'|' | awk '{gsub(","," ");print}'`

command1
perform action

command2
perform action

done