If condition

Shell Programming and Scripting
1

I am trying trying to find the percentage and compare it with a value.
But even if the condition is not true the also it is taking the true value not the else value.

x=`awk '{print $2}' out2.txt`
y=`awk '{print $4}' out2.txt`
z=$((100*$y/$x))
if [ ((100*$y/$x)) >90 ];then
  echo "high"   
else
  echo "low"
fi

Please suggest.

2

Please post what Operating System and version you are using and what Shell this is.

Assuming some sort of Posix Shell, this statement is faulty:
if [ ((100*$y/$x)) >90 ];then
It will create a file called "90" and always be "true".

To start with, try an integer comparison:

if [ $z -gt 90 ];then
3 
if [ $z -gt 90 ]

Hope you're aware that variable 'z' will hold only the integer part of (100 * $y / $x)