i know about ls, I know.... but some of our shares have a long messy list of acls and it is a lot to sort through.. without a grep option, unless you have a really nice one, is there a simple way to say: show me <USER> acl permissions on <SHARE> ?
ls -lR | awk '/^-/&&/user/ {printf "USER=%-10s PERM=%-10s", $3,$1}'
or for a spesific file who has permision 664:
find . -type f -name *.o -perm 664 -print