How to open multiple shells while the scripts keeps running.

UNIX for Beginners Q & A UNIX for Dummies Questions & Answers
1

Hello, I've tried for a while now to run a bash script that continues to the end, while opening new shells as needed.

I've tried


 xterm -e "somecommand"; &
 xterm -e " somecommand";

I've also tried

screen -S "somecommand"; &
screen -S "somecommand";

All without any luck, they both work but only open a new shell once the command has finished or I kill the process.
I really need the script to open multiple shells at the same time and continue till the end.

Any help or direction will be much appreciated.

Regards

2

You might want to post your script. I tried the following:

#!/bin/bash
echo "starting"
xterm -e "sleep 5"; &
echo "see the xterm"
ls
sleep 1
exit

And got a syntax error near unexpected token "&" - when I removed the ; and moved the & over one, then it ran with no issue (with the xterm popping up running the command and the original script continuing on and exiting before the xterm went away which I believe is what you are looking for)

3

Thanks RTM, after removing the ";" and moveing the "&" over it ran like a charm, all I have to do now is play around with "sleep" so the shell opens at the correct time.
Thanks again.
Regards

4

Hi there,

I've been trying to do something simular as discriber here with csh scripting with AIX.

When I excecute: xterm -e "sleep 5" with or without ; or & the xterm window opens but no command is being excecuted.

Any more suggestions?

Thanks for any help!
Robbert

5

I getting the error as

xterm: Can't execvp ls -ltr

any one has ideas abt this??

6

For Nilesrex: The error you received is should show more information.

In your example, is there anything more to the error message?

(Also, please start a new thread next time you have a question instead of hijacking someone else's thread - it makes it harder to answer everyone involved. Thanks.)