How to get desire line?

Hi Guys,

I am newbie here and greeting to all guys of unix forum, now I want to learn unix here.

I have query here, we have file where file has 20 line record, now i want display 10 to 15 line row record only, then how it possible.

Hello Aditya321,

Welcome to forum, we hope you will enjoy learning new things here.
Following may help you in same.

awk 'NR>=10 && NR<=15' Input_file

Thanks,
R. Singh

sed -n 10,15p file

Thank you so much Ravinder & Scrutinizer.

We can achieve this by head and tail command also.

head -n 15 file | tail -n 6 

how about

awk 'NR == 10, NR == 15 { print  $0 }' infile

you could use vi and then

:10,15w!/infile

or in perl

perl -ne 'print if 10..15' infile