How to get complete path in variable excluding last word?

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1

Hello Experts,

Can you please help me by providing a code which can give me the complete path except last word in a variable, the variable i can use anywhere else for my operation

eg:

if this below one is my path:

user/oracle/Test_admin/myfolder/bakup/part_bkptemp_part_bkp_repeated/list.txt

I want a code which can pull

user/oracle/Test_admin/myfolder/bakup/part_bkptemp_part_bkp_repeated/

in a variable excluding "list.txt" [last word.]

Please help:confused:

2

[MAN="dirname"]
dirname
[/MAN]

 
$ dirname "a/b/c.txt"
a/b
3 
$> VAR=user/oracle/Test_admin/myfolder/bakup/part_bkptemp_part_bkp_repeated/list.txt
$> echo ${VAR%/*}"/"
user/oracle/Test_admin/myfolder/bakup/part_bkptemp_part_bkp_repeated/

or

$> V=$(dirname user/oracle/Test_admin/myfolder/bakup/part_bkptemp_part_bkp_repeated/list.txt)`echo '/'`
$> echo $V
user/oracle/Test_admin/myfolder/bakup/part_bkptemp_part_bkp_repeated/

or

$> BLA=user/oracle/Test_admin/myfolder/bakup/part_bkptemp_part_bkp_repeated/list.txt
$> echo $BLA| sed 's/[^/]*$//'
user/oracle/Test_admin/myfolder/bakup/part_bkptemp_part_bkp_repeated/
4

thanks a lot

---------- Post updated at 02:56 AM ---------- Previous update was at 02:55 AM ----------

Awesome dude thanks