Help with awk - Disk usage

Shell Programming and Scripting
1

Hi All,

Would appreciate your help as to why the following code not showing the correct output. the issue is on the last else cause. I am trying to report on disk space based on percentage usage. for some reason, it's showing output as OK even thou disk space is 90% !!!! any ideas why? thanks!!

df -k | awk '
NR > 1 {

        _used=$5; sub(/%/,"",_used);
        if(_used >= 90)
                _status="CRITICAL"
        else if (_used >= 85)
                _status="WARN"
        else if (_used >= 75)
                _status="ATTEN"
        else _status="OK"

}
END { print _status }'

df -k
Filesystem     1K-blocks    Used Available Use% Mounted on
/dev/sda1        9288056 1218896   7597352  95% /
udev              505328       4    505324   1% /dev
tmpfs             205292     312    204980   1% /run
none                5120       0      5120   0% /run/lock
none              513228       0    513228   0% /run/shm
2

You print the status for the last disk mounted only. Try printing the status for every disk by moving the print from the END section into the "Normal" section right after the if ... else construct.

3

The code is putting a new value in _status on every line and it reports the last _status in the END section. The last line is OK, so that is what gets printed.