extracting only the filename without its extenstion

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1

Hi,

I have a requirement that i need to store only the filename without its extension. Can anyone please help me to do this.

For Example, i have stored the filename in a varialble called fname. I need to extract all the charecters before the first occurence of the dot.
If fname has value as PG_0008_20050519.xml.gz then i need to extract only "PG_0008_20050519". Please help me to do this.

TIA.

2

If the extension is always the same:

fname=`basename $fname xml.gz`

If the extension is not always the same:

fname=`echo $fname | cut -d\. -f1`
fname=${fname}.
3

Works Perfect.

Thanks a lot for the help.

4

some more ways

the first is one with awk
echo `basename <program-path>` | awk -F"." '{print $1}'

this one is with sed but no of characters in extension need to be known in prior
for 3 character extension
echo `basename <program-path>` | sed -e 's/\....//'

advancement to the above method, no of characters in extension need not be known

echo `basename <program-path>` | sed -e 's/\..*//'