Executing scripts in back ground

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1

Hi,

Test1.ksh
#! /bin/ksh
for i in $*
do
#echo "$i"
ksh test2.ksh $i &
done

test2.ksh
#! /bin/ksh
sleep 5s
echo "From Test 1 ==> $1"
exit 0;

I am executing as follows:
ksh test1.ksh a b c

Output is:
From Test 1 ==> a
From Test 1 ==> c
From Test 1 ==> b

After printing the last line its expecting the user to press the enter key to exit. Else its not quitting. How to quit that automatically ??

thanks in advance

2

use exit 1; at your functions' ends

3

Tired that too... Its not working .. It is expecting the user to press the enter key to exit back to the shell prompt.....

4

exit 0 <- will only work if error is encountered

5

Even without eixt its not working..

6

One thing you can do is this:

ksh test2.ksh $i > <filename> &

Re-direct your output to some other filename will solve the problem you mentioned but I don't know if this works for you..

cheers

7

thanks .. thats working ..

is there any other solution .. coz i may have a requirement like output should be displayed on the screen .. In that case your solution will not work ..

8

what I can think of at this moment is to kill the process at the end of your fuctions.. eg
PID=`ps -ef |grep Test | awk '{ print $1 }'`#ensure that PID is in column 1 ($1)
kill -9 ${PID}

9

All you have to do is insert "fg" in line after done in Test1.ksh file.
Your script are working in background; bring it into foreground to end.

#! /bin/ksh

for i in $*
do
#echo "$i"
ksh test2 $i &
done
fg

~/scripts/play % test1 a b c
From Test 1 ==> a
From Test 1 ==> b
From Test 1 ==> c
~/scripts/play %

10

Hi FunibonE...thanks...that works

11

hi funibone,
I am getting this error : test1.ksh[12]: fg: job control not enabled , when i added fg in test1.ksh
Also the test2.ksh did not start. Wat to do ??
hemant, can you please expalin how u tested that ??