escaping path

Shell Programming and Scripting
1

Hi
I use :

path=/var/www/admin
echo "$path" | sed -e 's/\//\\\//g'

this return

\/var\/www\/admin

and is ok.

but

path2=`echo "$path" | sed -e 's/\//\\\//g'`
echo $path2

return an error:

sed: -e expression #1, char 9: unknown option to `s'

Can anyone help me?
Thanks

2 
path2=$(echo "$path" | sed -e 's/\//\\\//g')
3

Thank you very much.
It's perfect.

4

You could save some backslash ( and avoid escaping the slash) by choosing another delimiter :

for example :

# echo "$PWD" | sed 's:/:\\/:g'

or

# echo "$PWD" | sed 's;/;\\/;g'