error

UNIX for Beginners Q & A UNIX for Dummies Questions & Answers
1

Hello
Any idea where is the error ?
*)
echo " Wrong selection. Try again "
continue
;;
esac
done
echo "Done"

Thanks alot

2

You can't have an "esac" unless you have a "case" first. Nor a "done" without a "do".

3

it gives an error like this
syntax error at line 43: `end of file' unexpected

the above code saws only the end of the script

ive got the case and do in my code

4

How to guess your whole script?

Pls. post your script to here.

5

echo " a.read a file"
echo " b.create a file"
echo " c.add on existing file"
echo " d. exit"
"; do
echo "Enter a,b,c or d: \c"
read answer
echo
case "$answer" in
a)

read answer
cat $answer
;;
b)

read answer
echo
cat> $answer
;;
c)

read answer
echo
cat>> $answer
;;
d)
break
;;
*)

continue
;;
esac
done
echo "Done"

6

What is the meaning of in line 5

"; do

??

You may use 'select' to do the same thing more convenience.

PS3="Enter your choice > "
select answer in "read a file" "create a file" "add on existing file" exit;
do
case "$answer" in
1)

read answer
cat $answer
;;
2)

read answer
echo
cat> $answer
;;
3)

read answer
echo
cat>> $answer
;;
4)
exit
;;
*)

print 'Invalid input'
;;
esac
done

7

I suppose this is what you were intending to do

Regards
JK

echo " a.read a file"
echo " b.create a file"
echo " c.add on existing file"
echo " d. exit"

while [ true ]
do
echo "Enter a,b,c or d: \c"
read answer
echo
case "$answer" in
a)
cat $answer
;;
b)
cat> $answer
;;
c)
cat>> $answer
;;
d)
exit
break
;;
*)
echo "option should be a, b or c"
;;
esac
done

8

Hi jayakhanna,

Do you know the first variable 'answer' not equal to the second 'answer' in 'case'? Try to think your script problem,

echo " a.read a file"
.
.
while [ true ]
do
echo "Enter a,b,c or d: \c"
read answer
echo
case "$answer" in
a)
cat $answer
;;

if I want to read a file, I press a. According to your 'case', it gives me 'cat a'. I know that you was confused with props' post.

9

Yeah I was very well aware that both of the variable are same, I assumed that he actually wanted a file name which is equivalent to the answer variable

Thanks and Regards
JK

10

It's true the OP does, but the $answer variable is used twice - once to store the option a,b,c or d and then to store the name of a file.

props, for the sanity of anyone looking at your program in the future (esp if the program is larger) you may want to use different variable names! :wink:

...
...
echo "Enter a,b,c or d: \c"
read option
case "$option" in
a)
read fileName
cat $fileName
;;
...
...
11

Thanks for your help . I really appreciate your replies:)