hi , i am trying to display the files created on a particular date. I have tried using find .-mtime +n but these files are created on november 6th 2007 , so i'm not sure of what the 'n' value should be. And the number of files created on that particular day are more than 5000 so i have to make a list of those files created along with the time and date of creation . Can anyone of you can help me out i achieving this.............
ls -l | grep "Nov 6" | awk '{print $9" "$6" "$7" "$8}'
This lists filename, Date, Time
Thanks alot man , its working .And i need another help , the files which are created are of the following format "index.log.08 Nov 07 03.29.15.zip" . This zip file is having spaces in its name , how can i delete file's of this type.
ls *\ *
Check if the above commands lists required files.
If it is successful then you can issue the dangerous rm command.
rm *\ *
Be cautious in removing files. Make sure the pattern matching works fine.
rm *\* isn't working man. Instead i've used ur command to create a file having a list of all the file's to be deleted. Using this command [COLOR="Red"]ls -l | grep "Apr 23" | awk '{print $9"|"$10"|"$11"|"$12}' > list_file.sh/COLOR] , this approach is working fine for all the files created on April 3 but now i've to modify this command to delete all the files created one month before the current calender date . Do you have any idea idea abt it ????
Soory , i meant April 23 in last post . The approach i'm trying is that i've written a shell script which call's this the command "ls -l | grep "Apr 23" | awk '{print $9"|"$10"|"$11"|"$12}' > list_file.properties" . I'm calling the file created by the above command in the same script and concatanate the various parameter's present in file line by line . There by deleting the file by firing the command rm "file name without spaces". This is working .Now I have to set up a cron to fire this script every month whereby it should delete the file created one month back.
May be you should have a look at Perderabo's datecalc