diplay user process in separate lines

Shell Programming and Scripting
1

hi
I m trying to display the processes of each user but its coming in one line like

george wilkins
PID TTY TIME CMD 7661 ? 00:00:01 sshd 7662 pts/6 00:00:00 bash
i want the output to be like
PID TTY TIME CMD
7661 ? 00:00:01 sshd
7662 pts/6 00:00:00 bash

my code is

proc=$(users)
for i in $proc
do
echo $(cat /etc/passwd | grep "$i" | cut -d ':' -f 5)
echo $(ps -u $i)
done

any idea how can i make it as a list
thanks

2

for i in `users`
do
cat /etc/passwd | grep \^"$i:" | cut -d ':' -f 5
ps -u $i
done

i.e. Put the output to standard output rather than into a shell variable.
The modified grep gives an exact match on username in the first field in passwd (e.g fred and freddy won't gove false matches).

3

sorry its still not working..My Question is to diplay the processes in line for each user
but its displaying in one line
PID TTY TIME CMD 10886 ? 00:00:00 sshd 10887 pts/3 00:00:00 bash
like this

4

thanks guys i got the soln
echo $(ps �u $i)
to:
echo �$(ps �u $i)�

5

Try this !!!

Code:

who|while read x ;
do
ps -u $x
done

You can also direct each o/p into separate files.

6 
nawk '{
for(i=1;i<NF/4;i++)
{
	printf $1" "$2" "$3" "$4" "
	for(j=(i*4+1);j<=(i+1)*4;j++)
		printf $j" "
	print ""
}
}' file