cutting field

Shell Programming and Scripting
1

Hi,

I have a var sdt='23032011000000'

now if i want only 23 out of above? hw to cut?

also..after cuttint-will it be stored in another var as a varchar or as a number?

2 
another_var=`echo  $sdt | cut -c 1-2`
3

Hi Thanks,

But after cutting will 23 be stored as a char or number in a var another_var..

because i am passing that var to a plsql procedure and there i am assigning it to a number..?

4 
sdt='23032011000000'; CutFld=$(echo $sdt | cut -c 1-2);echo $CutFld
5

it will be taken as number in your plsql procedure