How to count the number of files in a directory.
Thanks
Mahalakshmi.A
How to count the number of files in a directory.
Thanks
Mahalakshmi.A
I think this had been answered many times
only the count of files and not directories
ls -l | grep -c ^-
not sure if this is efficient tho
ls -l | grep -v drw | awk '{ print $9 }' | wc -l
you are assuming r and w perm for users if its a directory,
there need not be such a perm for user.
it could be even dr-x
in that case, your condition would fail to filter
Thanks for the replies which I had got.
Can you please explain me about awk '{print $9}' in ls -l | grep -v drw | awk '{ print $9 }' | wc -l
Thanks
Maha
hi,
grep -v use filter off anything that starts with drw like directories generally start with drw
wc is word count, -l used to display number of lines
awk '{ print $9 }' prints out the 9th column of the output
when you do a ls -l it prints out some file with
col1 col2 col3 col4 col5 col6 col7 col8 col9
-rw-r--r-- 1 root other 151 Nov 15 14:28 xx
drw-r--r-- 1 oracle dba 72 Nov 15 14:36 apple
enjoy
ls -l | grep -v drw | awk '{ print $9 }'
above command shows the 9th column of the grep o/p.
ex:
suppose o/p of the above grep command
-rwxr-xr-x 1 sri sri 317 Sep 20 16:18 get1
then o/p of awk command would be
get1
Thanks for the replies now I have started learning UNIX ... Day by day I shd improve.
I have another doubt
find /home/psv/datasources/ -type f -print > file_name
this file_name which I am specifying is stored as a new file. Can I store the output of the find command in a variable.
/usr/bin/python -c "import os; print len( [f for f in os.listdir(os.getcwd()) if os.path.isfile(f) ])"
var=`find . -name '*.*' -print`
echo $var
Hi All,
When i do ls -l on my current directory, there is an entry as follows.
-rw-r--r-- 1 sabraham bcc 0 Nov 17 07:58 0
Is this a system generated entry?
When i executed ls -l|grep -c ^- the resultant no of files is 1 less than the result of the command ls -l|grep -v d-w|awk '{ print $9}' |wc -l.
I assume that the result specified in the beginning is a directory and this attributes to the difference.
Any help on this would be appreciated.
using grep -v d-w
will include the
1) total tag and
2) directory for which owners-read permission is set ( drw is not equal to d-w )
hence the difference
What does this tag mean? When i execute the same with drw, d-w, dr- always i'm getting the same result. Can u please explain in detail.
Thanks in advance
Sumesh
you need to go with grep -v ^d ( to remove dirs from the list )