command help

Shell Programming and Scripting
1

In the command ls -la | awk '{print $5}' the command ouput for size is left to right I need it to be right to left

2

How do you mean? The fifth field is the size field... I don't get the bit about left to right and right to left...

3 
ls -la | awk '{len = length($5) > len ? length($5) : len ; arr[NR] = $5 }END{ for ( a = 1; a < NR; a++ ) { printf "%"len"s\n" , arr[a]}}'
4

I mean it printing the correct way with all the numbers lining up the way there supposed to. Test it you'll see what I mean.

That was awsome Reborg it worked perfect.

If I may ask will you please explain it to me.

Chris

5

Well that worked perfect until I put it into my app

What I am actually trying to do is

for f in $(<uploads); do 
    s=`echo "$PWD/$f"  | sed -e 's/^.*chris\.fileburst\.com/chris.fileburst.com/'`
    z=`ls -la "$f" | awk '{len = length($5) > len ? length($5) : len ; arr[NR] = $5 }END{ for ( a = 1; a < NR; a++ ) { printf "%"len"s\n" , arr[a]}}'`
    x=`ls -la "$f"| awk '{print $6,$7,$8}'`
    y=`md5sum "$f"| awk '{print $1}'`

echo -e "$s\t$z\t$x\t$y"

Now I know thats a long string and it was working with z=ls -la "$f" |awk '{print $5}' It just didn't print the size formatted left to right

Is there a way to incorporate what you gave me into that.

6

If anyone has any ideas I still really need help with this output. All the ideas I have had only works partially.

7

I don't have time to explain this code right now, but will post again later, I may be able to correct mistakes, but that depends on time.

#! /bin/awk -f
#
#  lineup.awk
#
BEGIN{
           maxf = 0
}
{
                sub ("^.*chris.fileburst.com", "chris.fileburst.com", $NF)
                # may need to adjust to the correct ouput for your system
                # keep values sequential
                     arr[NR,1] = $11
                     arr[NR,2] = $7
                     arr[NR,3] = $8
                     arr[NR,4] = $9
                     arr[NR,5] = $10
                     arr[NR,6] = $1
                # make sure you keep the i < value one greater that the 
                # number of entries in the array, same in the END block
                for ( i=1 ; i < 7; i++  ) {
                     if ( length(arr[NR, i]) > maxl ) maxl = length(arr[NR, i])
                }
}
END{
           for(x=1;x<=NR;x++){
                     for(y=1;y<7;y++){
                               if ( i == 2 ) {
                                   printf("%"maxl[y]"s ", arr[x,y])
                               }
                               else {
                                   printf("%-"maxl[y]"s ", arr[x,y])
                               }
                     }
                     printf("\n")
           }
}

The script becomes:

#!/bin/bash
while read file; do
      do echo $(md5sum $file) $(ls -l $PWD/$file)
done < uploads | ./lineup.awk