Calling shell script within shell script

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1

Hi All,

I have a simple script that has 8 more scripts being called within it.
Like below

Main Script.sh has within it like below
-----------------------

Script1.sh
Script2.sh
Script3.sh
Script4.sh
Script5.sh
Script6.sh
Script7.sh
Script8.sh

-----------------------------

Now I want 2 to run after 1 finishes and 3 after 2 and likewise until 8 as each script create a huge file which can take time to complete and it cannot be a fixed value(so cannot use sleep).

Please let me know will unix automatically wait for script 1 to finish for script 2 to start and so on

or

should I use (& and wait) combination to handle this.

Thanks

2

Your script as written above will not start Script2.sh until Script1.sh exits. As long as Script1.sh doesn't start anything asynchronously that hasn't completed before it exits; you will be fine.

3

Can you explain what you mean by asynchronously??

4

Asynchronously means that it contains a command that ends with & and exits without waiting for that command to complete; or calls a program that starts some processing in the background and exits before that background processing completes.