Bypass getopts errors and continue processing?

Shell Programming and Scripting
1

Is there a way to do this?

while getopts "n:g:m:i:p:d:a:" OPTION
do
   case $OPTION in
...

if i do a ./script.sh -n john -u user -p password, it will output:

 name= john
./script.sh: illegal option -- u

Is there a way to skip over errors so that -p will get processed as well?

By the way, ./script.sh -n john -u -p password will output:

name=john
password=password
./script.sh: illegal option --u

so I'm guessing the option with -u is the problem?

2

Why don't you just add 'u:' to getopts?

while getopts "n:g:m:i:u:d:a:" OPTION
3

Please when asking about shell programming specify your system, the first line of your script, shell you use, version of your shell, and give a working (or not working but full) example of your script.

4

I don't want a -u. And also, i'd want to handle cases where the user might input a wrong parameter with an option...

5

Are you saying you want to print a nice error message when the user enters an invalid option?

6

no, it already does print an error message, but it doesn't continue processing the rest of the arguments after the error...

7

I'd suggest that the script should exit if the user enters an invalid option.

However, I can think of a way around this.

---------- Post updated at 09:20 AM ---------- Previous update was at 09:11 AM ----------

Try this:
add the ':' at the begining of getopts.
add ?) to the case statement and do what you want in there.

while getopts ":dhqTv" OPT                              # While there is a command line option
do
   case $OPT in
      d)   
           ;;

      h)   print_options;;

      q)   
           ;;

      T)  
           ;;

      v)   
           ;;

      ?)   print_status_message "ERROR: Unknown flag encountered.\n" ERROR

           ;;

   esac
done                                            # end -
8

well what I want to do is continue processing the rest of the parameters instead of exiting the script...not sure how to do that