bash pattern

Shell Programming and Scripting
1

hi!

When I have a variable that contains the day let's say Sun06
and i want to check if my variable starts with any letter what pattern should I use?

I tried that one,but it returns syntax error..

if [ "$day" = ([A-Za-z]*) ]; then
2

I would use case instead of if :

case "$day" in
([A-Za-z]*) echo ok ;;
(*) echo ko ;;
esac
3

I would also have a preference for case since it is more portable. Since you are using bash you could also use:

if [[ "$day" == [A-Za-z]* ]]; then

--
@jlliagre: in light of our other interesting thread, the double quotes can be left out around the variable in the case statement ( case $day in )

4

it can also be left out the left hand side in bash's [[ :cool:

[[ $day = [[:alpha:]]* ]]
5

Ow, yes of course :b: Thanks neutronscott..