awk script help

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1

Dear Help,

I have an i/p file which looks like :

1 24 980
10 97 345
100 67 345
2 945 325
20 8 234

Is there a way to print it like, below format

  1  24 980
 10  97 345
100  67 345
  2 945 325
 20   8 234

Thx

2

Check format specifiers in printf()

3

Hello Indra2011,

Could you please try following and let me know if this helps.
This will only work for 3 fields.

awk 'FNR==NR{A=length($1)>A?length($1):A;D=length($2)>D?length($2):D;C=length($3)>C?length($3):C;next} {printf  "%"A"d %"D"d %d\n",$1, $2, $3}'  Input_file Input_file

Output will be as follows.

  1   24 980
 10   97 345
100   67 345
  2 9845 325
 20    8 234

Thanks,
R. Singh

4

As anbu23 said, printf (builtin in recent shells) will do what you want:

while read A B C; do printf "%3d %3d %3d\n" $A $B $C; done < file
  1  24 980
 10  97 345
100  67 345
  2 945 325
 20   8 234