Adding a line feed to each line

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1

Hi folks,

I did a search on this and didn't really find what fit my needs. I have a file with fixed record length of 436 bytes. I want to add a line feed x"0A" to the end x"0A" of each record(in byte 437). What's the easiest way to accomplish this?

Thanks.

2 
awk '{print $0"\x0a"}' file > outfile
3 
fold -w 436 file
4

I don't think the solution is that simple. As I read it the file consists of one record containing 436* number_of_logical_records characters.
Referring to post #2

5

I get an error message "awk: record `0000000007654592010-...' too long", which is referring to the first record in the file.

There are several thousand records in this file(when viewed in a file editor where the record length can be defined). However when opened in Notepad, etc it looks like one long record. If I understand the above, it looks like it is adding one line feed at the end of the file, since it would appear to be one long record.

6

Don't know what Operating System you have, but the general solution is to use the "dd" command.

Syntax can vary (see "man dd") but for example:

dd if=input_filename of=output_filename cbs=437 conv=unblock