while and do problems

Any ideas how to clear this error as it seems I dont understand if,do,while and els commands

#!/bin/ksh
set -x
print "This script creates test messages"
print "Please enter test case name"
read testcasename
echo $testcasename
 
skipfield=Y
while [ $skipfield != "Y" ]
print "Do you want to skip this field Y/N?"
read skipfield
do
done this done is causing syntax error 
 
CHOICE=N
while [ $CHOICE != "Y" ];
do
print "Please enter in field 1 Version"
read version
if [[ "${#version}" -lt 4 ]] ; then
print -n $version >> $testcasename
else
print "too many bytes"
fi
print "Do you want to continue Y/N?"
read CHOICE
done
CHOICE2=N
while [ $CHOICE2 != "Y" ];
do
print "Pleasent in field 2 Date"
read date
if [[ "${#date}" -lt 9 ]] ; then
print -n $date >> $testcasename
else
print "too many bytes"
fi
print "Do you want to continue Y/N?"
read CHOICE2
done

exit

two problems in this code fragment.

1. If skipfield != Y and before declare skipfield=Y, then never going to enter to while.
2. Position of do.

So I am doing this backwards?

This has been answered on your previous thread:
http://www.unix.com/shell-programming-scripting/173124-trouble-looping-script.html
Also the answer in post #2 shows the correct position of while, do, done.

# this is forever loop -almost, try to press CTRL-D ... loop will end
skipfield=Y
while [ $skipfield != "Y" ]
print "Do you want to skip this field Y/N?"
read skipfield
do
      :   # between do and done, like then and fi need 1-n commands
         #  :  = builtin nop command, return always true
done

Why ?
while command(s)
do
...
done
=> exit code of command, between while and do you can put command lines, but return code of last line is the important.
=> read some and press EOF = exit code is not 0 => while end

So, maybe this is better:

# this will end if you press Y or CTRL-D
while
     print "Do you want to skip this field Y/N?"
     read skipfield
     [ "$skipfield" != "Y" ]  # - without " " you get error if press ENTER or CTRL-D
do
      : 
done